document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154885>Question 154885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne and Nancy use a metal alloy that is 24.9% copper to make jewelry. How many ounces of a 20% alloy must be mixed with a 27% alloy to form 100 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114084 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .27x+.20(100-x)=.249*100<BR>\n" );
document.write( ".27x+20-.20x=24.9<BR>\n" );
document.write( ".07x=24.9-20<BR>\n" );
document.write( ".07x=4.9<BR>\n" );
document.write( "x=4.9/.07<BR>\n" );
document.write( "x=70 oz. of 27% alloy is needed.<BR>\n" );
document.write( "100-70=30 oz. of 20% alloy is needed.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( ".27*70+.20*30=24.9<BR>\n" );
document.write( "18.9+6=24.9<BR>\n" );
document.write( "24.9=24.9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );