document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154933>Question 154933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you figure this out when y is isolated on both equations:<BR>\n" );
document.write( "y=3x+1<BR>\n" );
document.write( "y=6x-1\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114068 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The easiest way to solve this system of equations is:<BR>\n" );
document.write( "As y is equal to both 3x + 1 and 6x - 1, so <BR>\n" );
document.write( "6x - 1 = 3x + 1<BR>\n" );
document.write( "Solving it for x, we have<BR>\n" );
document.write( "3x = 2<BR>\n" );
document.write( "so x = 2/3<BR>\n" );
document.write( "Substituting x = 2/3 into y = 3x + 1, we have<BR>\n" );
document.write( "y = 3*(2/3) + 1 = 3<BR>\n" );
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document.write( "ALTERNATIVE SOLUTION:<BR>\n" );
document.write( "Change the system into standard form.<BR>\n" );
document.write( "-3x + y = 1<BR>\n" );
document.write( "-6x + y = -1<BR>\n" );
document.write( "then solve it.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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