document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154933>Question 154933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you figure this out when y is isolated on both equations:<BR>\n" );
document.write( "y=3x+1<BR>\n" );
document.write( "y=6x-1\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #114066 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=114066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you figure this out when y is isolated on both equations:<BR>\n" );
document.write( "y=3x+1<BR>\n" );
document.write( "y=6x-1 <BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Since both are \"y\", they can be substituted to give:<BR>\n" );
document.write( "3x + 1 = 6x -1<BR>\n" );
document.write( "3x = 2<BR>\n" );
document.write( "x = 2/3<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Substitute into y=3x+1 to solve for \"y\":<BR>\n" );
document.write( "y = 3(2/3) = 2<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "Ans: x = 2/3 ; y = 2<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );