document.write( "Question 154824: A mother is 25 years older than her daughter. Ten years ago, the daughter is 4/9 of the age of the mother was then. Find the age of each. \n" ); document.write( "
Algebra.Com's Answer #114048 by nerdybill(7384)\"\" \"About 
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A mother is 25 years older than her daughter. Ten years ago, the daughter is 4/9 of the age of the mother was then. Find the age of each.
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\n" ); document.write( "Let D = daughter's age
\n" ); document.write( "then
\n" ); document.write( "D+25 = Mother's age
\n" ); document.write( "(from:\"A mother is 25 years older than her daughter.\")
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\n" ); document.write( "We derive our equation from:
\n" ); document.write( "\"Ten years ago, the daughter is 4/9 of the age of the mother was then.\"
\n" ); document.write( "to get:
\n" ); document.write( "D-10 = (4/9)([D+25]-10)
\n" ); document.write( "D-10 = (4/9)(D+25-10)
\n" ); document.write( "D-10 = (4/9)(D+15)
\n" ); document.write( "9D-90 = (4)(D+15)
\n" ); document.write( "9D-90 = 4D+60
\n" ); document.write( "5D-90 = 60
\n" ); document.write( "5D = 150
\n" ); document.write( "D = 30 years (daughter's age)
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\n" ); document.write( "D+25 = 30+25 = 55 years (Mothers age)
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