document.write( "Question 23019: I know there's a similar problem, but got very confused by the way the set-up was formatted in the response. Can someone pllleeeeease help? All I need is to see which numbers & variables go where, then I should be able to solve it. Thanks in advance!\r
\n" );
document.write( "\n" );
document.write( "In still water a boat can travel 15 mph. It travels 36 miles upstream & 36 miles downstream in a total time of 5 hours. Find the speed of the current. (The book says the answer is 3 mph) \n" );
document.write( "
Algebra.Com's Answer #11404 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = speed of the current \n" ); document.write( "15 +x = speed of the boat downstream (with the current) \n" ); document.write( "15-x = speed of the boat upstream (against the current) \n" ); document.write( "Distance upstream = Distance downstream = 36 miles\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "D=RT \n" ); document.write( "T= D/R\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Total Time = D/R + D/R = 5 hours \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the LCD which is (15+x)(15-x): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x= 3 or x= -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Reject the negative answer. x=3 mph = speed of the current.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |