document.write( "Question 154768This question is from textbook
\n" ); document.write( ": For security a company will enclose a rectangle area of 11,200 ft^2 in the rear of its plant. One side will be bound by the building and the other three sides by fencing .If 300ft of fencing will be used, what will be the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #114000 by checkley77(12844)\"\" \"About 
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XY=11,200
\n" ); document.write( "2X+Y=300 OR Y=300-2X
\n" ); document.write( "X(300-2X)=11,200
\n" ); document.write( "300X-2X^2=11,200
\n" ); document.write( "2X^2-300X+11,200=0
\n" ); document.write( "2(X^2-150X+5,600)=0
\n" ); document.write( "2(X-70)(X-80)=0
\n" ); document.write( "X-70=0
\n" ); document.write( "X=70 FOR THE TWO SHORT SIDE
\n" ); document.write( "2*70+Y=300
\n" ); document.write( "140+Y=300
\n" ); document.write( "Y=300-140
\n" ); document.write( "Y=160 THE SINGLE LONG SIDE.
\n" ); document.write( "PROOF:
\n" ); document.write( "70*160=11,200
\n" ); document.write( "11.200
\n" ); document.write( "OR:
\n" ); document.write( "X-80=0
\n" ); document.write( "X=80 FOR THE TWO SHORT SIDES.
\n" ); document.write( "2*80+Y=300
\n" ); document.write( "160=Y=300
\n" ); document.write( "Y=300-160
\n" ); document.write( "X=140 FOR THE SINGLE LONG SIDE.
\n" ); document.write( "PROOF:
\n" ); document.write( "80*140=11,200
\n" ); document.write( "11,200=11,200
\n" ); document.write( " \n" ); document.write( "
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