document.write( "Question 154829: In two years, Edgard will be three-fourths as old as his sister, Edna. Two years ago, he was two-thirds as old as she. How old are they? \n" ); document.write( "
Algebra.Com's Answer #113995 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! x+2=3y/4 or x=3y/4-2 \n" ); document.write( "x-2=2y/3 \n" ); document.write( "(3y/4-2)-2=2y/3 \n" ); document.write( "(3y-2*4)/4-2=2y/3 \n" ); document.write( "(3y-8)/4-2=2y/3 \n" ); document.write( "(3y-8-2*4)/4=2y/3 \n" ); document.write( "(3y-8-8)/4=2y/3 \n" ); document.write( "(3y-16)/4=2y/3 cross multiply. \n" ); document.write( "3(3y-16)=4*2y \n" ); document.write( "9y-48=8y \n" ); document.write( "9y-8y=48 \n" ); document.write( "y=48 age of Edgard now. \n" ); document.write( "x=3*48/4-2 \n" ); document.write( "x=3*12-2 \n" ); document.write( "x=36-2 \n" ); document.write( "x=34 age of Edna now. \n" ); document.write( "Proof: \n" ); document.write( "34-2=2*48/3 \n" ); document.write( "32=96/3 \n" ); document.write( "32=32 \n" ); document.write( " \n" ); document.write( " |