document.write( "Question 154779This question is from textbook beginning and intermediate algebra
\n" ); document.write( ": a=3b-1
\n" ); document.write( "b=2a+2
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Algebra.Com's Answer #113972 by Alan3354(69443)\"\" \"About 
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a=3b-1
\n" ); document.write( "b=2a+2
\n" ); document.write( "-------
\n" ); document.write( "Since eqn 1 already shows a as a function of b, substitute for a in eqn 2.
\n" ); document.write( "b=2*(3b-1)+2
\n" ); document.write( "b=6b-2+2
\n" ); document.write( "b = 6b
\n" ); document.write( "b = 0 (the only possibility)
\n" ); document.write( "------------
\n" ); document.write( "Sub b into eqn 1
\n" ); document.write( "a = 3*0-1
\n" ); document.write( "a = -1
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