document.write( "Question 23014: log 5+log (n+1)=log 6n
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Algebra.Com's Answer #11396 by rapaljer(4671)\"\" \"About 
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\"log%289%2C5%29+%2B+log%289%2C%28n%2B1%29%29+=+log%289%2C6n%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28b%2CM%29+%2B+log%28b%2CN%29+=+log%28b%2CMN%29\", so \"log%289%2C5%29+%2B+log%289%2C%28n%2B1%29%29+=+log%289%2C5%28n%2B1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%289%2C+5%28n%2B1%29%29+=+log%289%2C6n%29\"\r
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\n" ); document.write( "\n" ); document.write( "If \"log%28b%2C+M%29+=+log%28b%2C+N%29\", then \"M=N\"\r
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\n" ); document.write( "\n" ); document.write( "5(n+1) = 6n
\n" ); document.write( "5n+5 = 6n\r
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\n" ); document.write( "\n" ); document.write( "Subtract 5n from each side:
\n" ); document.write( "5= n
\n" ); document.write( "Remember to check the value of n to make sure you don't have a log of a negative number. You do not, so the answer n=5 is acceptable.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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