document.write( "Question 154708: Arthur can arrange a number of books in the bookshelf in x hours. Charlie can do the same job in y hours. If they work together,they will finish the same job in 6 hours. Arthur's rate is one-third of Charlie's. Find the number of hours each can do the job alone? \n" ); document.write( "
Algebra.Com's Answer #113924 by checkley77(12844)\"\" \"About 
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XY/(X+Y)=6
\n" ); document.write( "Y=X/3
\n" ); document.write( "(X*X/3)/(X+X/3)=6
\n" ); document.write( "X^2/3=6(3X+X)/3
\n" ); document.write( "X^2/3=2*4X
\n" ); document.write( "X^2=3*8X
\n" ); document.write( "X^2=24X
\n" ); document.write( "X^2-24X=0
\n" ); document.write( "X(X-24)=0
\n" ); document.write( "X=24 HOURS FOR ARTHUR WORKING ALONE.
\n" ); document.write( "24/3=8 HOURS FOR CHARLIE WORKING ALONE.
\n" ); document.write( "PROOF:
\n" ); document.write( "24*8/(24+8)=6
\n" ); document.write( "192/32=6
\n" ); document.write( "6=6
\n" ); document.write( "
\n" );