document.write( "Question 154708: Arthur can arrange a number of books in the bookshelf in x hours. Charlie can do the same job in y hours. If they work together,they will finish the same job in 6 hours. Arthur's rate is one-third of Charlie's. Find the number of hours each can do the job alone? \n" ); document.write( "
Algebra.Com's Answer #113924 by checkley77(12844) ![]() You can put this solution on YOUR website! XY/(X+Y)=6 \n" ); document.write( "Y=X/3 \n" ); document.write( "(X*X/3)/(X+X/3)=6 \n" ); document.write( "X^2/3=6(3X+X)/3 \n" ); document.write( "X^2/3=2*4X \n" ); document.write( "X^2=3*8X \n" ); document.write( "X^2=24X \n" ); document.write( "X^2-24X=0 \n" ); document.write( "X(X-24)=0 \n" ); document.write( "X=24 HOURS FOR ARTHUR WORKING ALONE. \n" ); document.write( "24/3=8 HOURS FOR CHARLIE WORKING ALONE. \n" ); document.write( "PROOF: \n" ); document.write( "24*8/(24+8)=6 \n" ); document.write( "192/32=6 \n" ); document.write( "6=6 \n" ); document.write( " |