document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154657>Question 154657</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>Algebra structure and method book 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve this problem and show all work using the 5-step method: (((A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113919 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME OR DISTANCE/TIME=RATE<BR>\n" );
document.write( "20/3=6.666 WITH THE CURRENT.<BR>\n" );
document.write( "20/4=5 AGAINST THE CURRENT.<BR>\n" );
document.write( "(6.666-5)/2=1.666/2=.833MPH IS THE SPEED OF THE CURRENT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6.666-.833=5.833 SPEED OF THE SAIL BOAT.<BR>\n" );
document.write( "5+.833=5.833 DITTO.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );