document.write( "Question 23001: __________________2
\n" ); document.write( "log (3x-1)=log (2x )
\n" ); document.write( "___8__________8\r
\n" ); document.write( "\n" ); document.write( "im sorry i dont really know how to type those on the computer but the to is for 2x squared and the 8s are supposed to be log and then the little 8 thing
\n" ); document.write( "I dont really know how to do this stuff so if you could show me one i would know how to do it\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #11391 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let me take a shot at it anyway. Is this what you mean:\r
\n" ); document.write( "\n" ); document.write( "\"log%288%2C%283x-1%29%29+=+log%288%2C%282x%29%5E2%29+\"???\r
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\n" ); document.write( "\n" ); document.write( "If that is the question, then you can say that if \"log%28b%2C+x%29=log%28b%2Cy%29\", then \"x=y\".\r
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\n" ); document.write( "\n" ); document.write( "Likewise, \"log%288%2C%283x-1%29%29+=+log%288%2C%282x%29%5E2%29+\" means that \"3x-1=+%282x%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"3x-1+=+4x%5E2\", which is a quadratic equation. Get this equal to zero by adding -3x +1 to each side of the equation:\r
\n" ); document.write( "\n" ); document.write( "\"0=4x%5E2+-3x+%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "This does not factors so you'll have to solve by quadratic formula. Before I go to a lot of trouble to do that, let's check to see if I copied the problem correctly. You can repost this or send me an Email to finish the problem.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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