document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154642>Question 154642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A straight line passes through the point (4,3) and is perpendicular to the line joining the points (-1,3) and (1,-1). Find the equation of this line. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113893 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A straight line passes through the point (4,3) and is perpendicular to the line joining the points (-1,3) and (1,-1). Find the equation of this line.<BR>\n" );
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document.write( "Find the slope of the line thru the 2 points:<BR>\n" );
document.write( "m1 = (y2 - y1)/(x2 - x1)<BR>\n" );
document.write( "m1 = (-1 -3)/(1 -(-1))<BR>\n" );
document.write( "m1 = -4/2 = -2<BR>\n" );
document.write( "To be perpendicular, the slope m2 is the negative inverse of m1, -1/m1<BR>\n" );
document.write( "m2 = 1/2<BR>\n" );
document.write( "Use (x3,y3) = (4,3)<BR>\n" );
document.write( "y - y3 = m2*(x - x3)<BR>\n" );
document.write( "y - 3 = (1/2)*(x - 4)<BR>\n" );
document.write( "2y - 6 = x - 4<BR>\n" );
document.write( "x - 2y = -2<BR>\n" );
document.write( " </SPAN>\n" );
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