document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154656>Question 154656</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh>Algebra structure and method book 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me solve by either the substitution or the additon-or-subtraction method: (((2m=n-3 3m-2n-9))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113892 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (((2m=n-3 3m-2n-9)))<BR>\n" );
document.write( "I assume you mean 2 equations:<BR>\n" );
document.write( "2m = n-3<BR>\n" );
document.write( "3m-2n = 9<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "2m - n = -3<BR>\n" );
document.write( "3m -2n = 9<BR>\n" );
document.write( "Mult by the 1st eqn by 2<BR>\n" );
document.write( "4m -2n = -6<BR>\n" );
document.write( "Subtract it from the 2nd eqn<BR>\n" );
document.write( "-m +0n = -12<BR>\n" );
document.write( "m = 12<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Sub into either eqn<BR>\n" );
document.write( "2*12 - n = -3<BR>\n" );
document.write( "24 - n = -3<BR>\n" );
document.write( "-n = -27<BR>\n" );
document.write( "n = 27<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );