document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154631>Question 154631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 70% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113870 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 70% acid solution?<BR>\n" );
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document.write( "Let x = gallons of pure acid to be added<BR>\n" );
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document.write( "The equation is derived from:<BR>\n" );
document.write( "\"acid added from pure acid solution\" + \"acid from 40% solution\" = <BR>\n" );
document.write( "\"70% of total solution\"<BR>\n" );
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document.write( "x + .40(2) = .70(2+x)<BR>\n" );
document.write( "x + .80 = 1.40 + .70x<BR>\n" );
document.write( ".30x = .60<BR>\n" );
document.write( "x = 2 gallons\r<BR>\n" );
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document.write( " </SPAN>\n" );
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