document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154551>Question 154551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ANGELA WANTS 20QUARTS OF 50% ANTIFREEZE. SHE HAS 40% SOLUTIO. SHE WANTS TO MAKE IT STRONGER BY ADDING PURE ANTIFREEZE. CONTRUCT TABLE....\r<BR>\n" );
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document.write( "TABLE FOUR COLUMS DOWN AND ACROSS\r<BR>\n" );
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document.write( "            -------CONCENTRATION ---AMOUNT----AMOUNT OF ANTIFREEZE\r<BR>\n" );
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document.write( "PURE           <BR>\n" );
document.write( "ANTIFREEZE     \r<BR>\n" );
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document.write( "40%\r<BR>\n" );
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document.write( "TOTAL<BR>\n" );
document.write( "WHAT NGELA<BR>\n" );
document.write( "WANTS THE<BR>\n" );
document.write( "GOAL\r<BR>\n" );
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document.write( "SOLVE WITH ONE VARIABLE SINCE THE TOTAL IS 100.<BR>\n" );
document.write( "1QUART RELATES TO X AND THE OTHER TO 100-X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113868 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of pure antifreeze that needs to be added<BR>\n" );
document.write( "Then 20-x=amount of 40% solution that needs to be used\r<BR>\n" );
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document.write( "Now we know that the amount of pure antifreeze in the 40% solution(0.40(20-x)) plus the amount of pure antifreeze added (x) has to equal the amount of pure antifreeze in the final solution (20*0.50) So our equation to solve is:\r<BR>\n" );
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document.write( "0.40(20-x)+x=20*0.50 get rid of parens and simplify\r<BR>\n" );
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document.write( "8-0.40x+x=10  subtract 8 from each side<BR>\n" );
document.write( "8-8-0.40x+x=10-8  collect like terms\r<BR>\n" );
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document.write( "0.60x=2  divide both sides by 0.60<BR>\n" );
document.write( "x=3.33 qts -----------amount of pure antifreeze that needs to be added\r<BR>\n" );
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document.write( "20-x=20-3.33=16.67 qts------------amount of 40% antifreeze used\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "16*67*0.40+3.33=10<BR>\n" );
document.write( "6.668+3.333=10<BR>\n" );
document.write( "10~~~10\r<BR>\n" );
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document.write( "You do the chart\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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