document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154620>Question 154620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am helping my daughter and trying to find the rule on determining the least common denominator.  This is from worksheets in Algebra I but doesn't involve a book yet.  I am trying to foind the LCD with two different fractions.\r<BR>\n" );
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document.write( "Thanks.<BR>\n" );
document.write( "Mark </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113860 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Example:<BR>\n" );
document.write( "Let's say you have 1/24 + 1/75 and want the lcd.<BR>\n" );
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document.write( "Find the prime-factor form of each denominator:<BR>\n" );
document.write( "24 = 2^3*3<BR>\n" );
document.write( "75 = 3*5^2<BR>\n" );
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document.write( "The lcd must contain each of the prime numbers to the highest power present<BR>\n" );
document.write( "in the denominators.<BR>\n" );
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document.write( "So the lcd must have 2,3,and 5 to the highest power present in the <BR>\n" );
document.write( "denominators.<BR>\n" );
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document.write( "the lcd is (2^3)* (3) * (5^2) = 8*3*25 = \r<BR>\n" );
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document.write( "So, does that work?<BR>\n" );
document.write( "The problem was 1/24 + 1/75<BR>\n" );
document.write( "Rewrite each fraction with the lcd as its denominator:<BR>\n" );
document.write( "Divide 24 into 600 to get 25.<BR>\n" );
document.write( "Multiply numerator and denominator of the 1st fraction by 25 to get:<BR>\n" );
document.write( "25/600<BR>\n" );
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document.write( "Divide 75 into 600 to get 8<BR>\n" );
document.write( "Multiply numerator and denominator of the 2nd fraction by 8 to get:<BR>\n" );
document.write( "8/600<BR>\n" );
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document.write( "Add the two resulting fractions to get:<BR>\n" );
document.write( "1/24 + 1/75 = 25/600 + 8/600 = 33/600 = 11/200<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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