document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154622>Question 154622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hey i would really appreciate it if you could solve this combinatorics problem for me:<BR>\n" );
document.write( "P(n,3)= 2C(n,2), n&#1013;N. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113856 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(n,3)= 2C(n,2)<BR>\n" );
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document.write( "n!/(n-3)! = 2[n!/(n-2)!2!]\r<BR>\n" );
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document.write( "Cancel the n! and the 2, both of which are common factors to get:\r<BR>\n" );
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document.write( "1/(n-3)! = 1/(n-2)!\r<BR>\n" );
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document.write( "Invert to get:\r<BR>\n" );
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document.write( "(n-3)! = (n-2)!\r<BR>\n" );
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document.write( "(n-3)! = (n-2)(n-3)!\r<BR>\n" );
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document.write( "Divide both sides by (n-3)!\r<BR>\n" );
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document.write( "n-2 = 1<BR>\n" );
document.write( "n = 3<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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