document.write( "Question 154609This question is from textbook elementary and intermediate algebra
\n" ); document.write( ": I really need help please on this graphic equation. I need to draw a graph of an equation that contains two x-intercepts, -2 and 3. At the x intercept -2, the graph crosses the x-axis; at the x-intercept 3 the graph touches the x-axis. I'm lost!!! There are no ordered pairs so what shall I do? Help me please!!! \n" ); document.write( "
Algebra.Com's Answer #113845 by ankor@dixie-net.com(22740)\"\" \"About 
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draw a graph of an equation that contains two x-intercepts, -2 and 3.
\n" ); document.write( ":
\n" ); document.write( "Write the equation for this; we know x=-2 and x=3
\n" ); document.write( "Therefore the factors can be (x+2)(x-3) = 0
\n" ); document.write( "FOIL these and you have:
\n" ); document.write( "x^2 - 3x + 2x - 6 = 0
\n" ); document.write( "x^2 - x - 6 = 0 is the equation
\n" ); document.write( ":
\n" ); document.write( "Plot y = x^2 - x - 6, for x = -4 to x = +5, it should look like this:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+10%2C+-10%2C+10%2C+x%5E2-x-6%29+\"
\n" ); document.write( "Note the x intercepts are x=-2 and x=+3 \n" ); document.write( "
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