document.write( "Question 154584: .
\n" ); document.write( "........................................................................................an inlet pipe can filla tank in 1 hour, a drain pipe can empty it in 3/2 hours. The inlet pipe was openend at 6:00 a.m. to fill the tank. At 6:20a.m. someone noticed that the drain has been left open and so he closes it immediately. How long will it take the first pipe to finish filling
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Algebra.Com's Answer #113841 by ankor@dixie-net.com(22740)\"\" \"About 
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An inlet pipe can fill a tank in 1 hour; a drain pipe can empty it in 3/2 hours. The inlet pipe was opened at 6:00 a.m. to fill the tank. At 6:20 a.m. someone noticed that the drain has been left open and so he closes it immediately. How long will it take the first pipe to finish filling.
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\n" ); document.write( "Let's deal in minutes here:
\n" ); document.write( "Inlet time = 60 min
\n" ); document.write( "Drain time = 90 min
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\n" ); document.write( "let t = time (in minutes) required to finish filling the tank.
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\n" ); document.write( "Let the full tank = 1:
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\n" ); document.write( "Total on time for the inlet pipe = (t+20)
\n" ); document.write( "On time for the drain = 20 min
\n" ); document.write( ":
\n" ); document.write( "\"%28%28t%2B20%29%29%2F60\" - \"20%2F90\" = 1
\n" ); document.write( "Multiply equation by 180 to get rid of the denominators, results:
\n" ); document.write( "3(t+20) - 2(20) = 180
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\n" ); document.write( "3t + 60 - 40 = 180
\n" ); document.write( "3t + 20 = 180
\n" ); document.write( "3t = 180 - 20
\n" ); document.write( "3t = 160
\n" ); document.write( "t = \"160%2F3\"
\n" ); document.write( "t = 53.333 min or 53 min 20 sec to finish filling the tank
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\n" ); document.write( "Check with calc (inlet time: 53.33 + 20 = 73.33)
\n" ); document.write( "(73.33/60) - (20/90) = 1
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