document.write( "Question 154584: .
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document.write( "........................................................................................an inlet pipe can filla tank in 1 hour, a drain pipe can empty it in 3/2 hours. The inlet pipe was openend at 6:00 a.m. to fill the tank. At 6:20a.m. someone noticed that the drain has been left open and so he closes it immediately. How long will it take the first pipe to finish filling \n" );
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Algebra.Com's Answer #113841 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An inlet pipe can fill a tank in 1 hour; a drain pipe can empty it in 3/2 hours. The inlet pipe was opened at 6:00 a.m. to fill the tank. At 6:20 a.m. someone noticed that the drain has been left open and so he closes it immediately. How long will it take the first pipe to finish filling. \n" ); document.write( ": \n" ); document.write( "Let's deal in minutes here: \n" ); document.write( "Inlet time = 60 min \n" ); document.write( "Drain time = 90 min \n" ); document.write( ": \n" ); document.write( "let t = time (in minutes) required to finish filling the tank. \n" ); document.write( ": \n" ); document.write( "Let the full tank = 1: \n" ); document.write( ": \n" ); document.write( "Total on time for the inlet pipe = (t+20) \n" ); document.write( "On time for the drain = 20 min \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Multiply equation by 180 to get rid of the denominators, results: \n" ); document.write( "3(t+20) - 2(20) = 180 \n" ); document.write( ": \n" ); document.write( "3t + 60 - 40 = 180 \n" ); document.write( "3t + 20 = 180 \n" ); document.write( "3t = 180 - 20 \n" ); document.write( "3t = 160 \n" ); document.write( "t = \n" ); document.write( "t = 53.333 min or 53 min 20 sec to finish filling the tank \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check with calc (inlet time: 53.33 + 20 = 73.33) \n" ); document.write( "(73.33/60) - (20/90) = 1 \n" ); document.write( " \n" ); document.write( " |