document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154582>Question 154582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If spherical metal ball has a mass of 1.00E3 g and a density of 10.9 g/mL. What is its diameter (in cm)?\r<BR>\n" );
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document.write( "The volume of a sphere can be calculated using V= (4/3)&#960;r3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113818 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If spherical metal ball has a mass of 1.00E3 g and a density of 10.9 g/mL. What is its diameter (in cm)? <BR>\n" );
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document.write( "Mass = Volume x Density<BR>\n" );
document.write( "1000 = V*10.9<BR>\n" );
document.write( "V = 1000/10.9 = (4/3)*PI*r^3<BR>\n" );
document.write( "r^3 = 1000/(10.9*(4/3)*PI<BR>\n" );
document.write( "r^3 = 3000/(10.9*4*PI)<BR>\n" );
document.write( "r^3 = 21.902<BR>\n" );
document.write( "r = 2.79787... cm<BR>\n" );
document.write( "D = r*2 = 5.55974... cm </SPAN>\n" );
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