document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154580>Question 154580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle measures 43 less than six times the measure of its complement. Find the messure of both angles. I just need to know how to set these up I tried and got 6x-43=90 but i couldnt figure out the \"43 less than\" part  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113817 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the angle you are tryng to find = A.<BR>\n" );
document.write( "The complement of angle A = (90-A) and 6 times this complement is 6(90-A) and 43 less than that is 6(90-A)-43, so you can write:<BR>\n" );
document.write( "A = 6(90-A)-43 Simplify and solve for A.<BR>\n" );
document.write( "A = 540-6A-43<BR>\n" );
document.write( "A = 497-6A  Add 6A to both sides.<BR>\n" );
document.write( "7A = 497  Divide both sides by 7.<BR>\n" );
document.write( "A = 71 degrees<BR>\n" );
document.write( "The complement of A = 90-A = 09-71 = 19 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );