document.write( "Question 22995: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
\n" ); document.write( "I did not get the answer to this problem, so if you could please give me some solutions.
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Algebra.Com's Answer #11381 by rapaljer(4671)\"\" \"About 
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If Sally can paint the house in 4 hours, then in 1 hour she can paint 1/4 of the house.\r
\n" ); document.write( "\n" ); document.write( "If John can paint the house in 6 hours, then in 1 hour he can paint 1/6 of the house.\r
\n" ); document.write( "\n" ); document.write( "Let x = number of hours it would take them together to paint the house, then working together, in 1 hour they can paint 1/x of the house. \r
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\n" ); document.write( "\n" ); document.write( "The equation is this:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F4+%2B+1%2F6+=+1%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by the LCD which is 12x:
\n" ); document.write( "\"%2812x%29%2A+%281%2F4%29+%2B+%2812x%29%2A%281%2F6%29+=+%2812x%29%2A%281%2Fx%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+2x+=+12\"
\n" ); document.write( "\"5x+=+12\"
\n" ); document.write( "\"x+=+12%2F5\" = 2.4 hours\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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