document.write( "Question 22995: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
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document.write( "I did not get the answer to this problem, so if you could please give me some solutions. \n" );
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Algebra.Com's Answer #11381 by rapaljer(4671) You can put this solution on YOUR website! If Sally can paint the house in 4 hours, then in 1 hour she can paint 1/4 of the house.\r \n" ); document.write( "\n" ); document.write( "If John can paint the house in 6 hours, then in 1 hour he can paint 1/6 of the house.\r \n" ); document.write( "\n" ); document.write( "Let x = number of hours it would take them together to paint the house, then working together, in 1 hour they can paint 1/x of the house. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is this:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides by the LCD which is 12x: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |