document.write( "Question 154511: Determine whether or not if it can be factored. If not, then state it is prime.
\n" ); document.write( "3x^2 + 5x - 1
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Algebra.Com's Answer #113808 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Looking at the expression \"3x%5E2%2B5x-1\", we can see that the first coefficient is \"3\", the second coefficient is \"5\", and the last term is \"-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"3\" by the last term \"-1\" to get \"%283%29%28-1%29=-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-3\" (the previous product) and add to the second coefficient \"5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-3\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-3\":\r
\n" ); document.write( "\n" ); document.write( "1,3\r
\n" ); document.write( "\n" ); document.write( "-1,-3\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-3\".\r
\n" ); document.write( "\n" ); document.write( "1*(-3)
\n" ); document.write( "(-1)*(3)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"5\":\r
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First NumberSecond NumberSum
1-31+(-3)=-2
-13-1+3=2
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that there are no pairs of numbers which add to \"5\". So \"3x%5E2%2B5x-1\" cannot be factored. This means that the polynomial is prime.
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