document.write( "Question 154536: How long would it take for $100 to become $1000 if it is invested at an 8% annual interest rate that is compounded quarterly? \n" ); document.write( "
Algebra.Com's Answer #113790 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
How long would it take for $100 to become $1000 if it is invested at an 8% annual interest rate that is compounded quarterly?
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "\"A+=+P%281%2Br%2Fn%29%5E%28nt%29\"\r\n" );
document.write( "\r\n" );
document.write( "where P = beginning amount = 100\r\n" );
document.write( "      A = final amount = 1000 \r\n" );
document.write( "      r = rate expressed as a decimal = .08\r\n" );
document.write( "      n = 4 (quarterly means compounded 4 times a year)\r\n" );
document.write( "      t = ? (number of years, the unknown)\r\n" );
document.write( "\r\n" );
document.write( "\"1000+=+100%281%2B.08%2F4%29%5E%284t%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"1000+=+100%281%2B.02%29%5E%284t%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"1000+=+100%281.02%29%5E%284t%29\"\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by 100\r\n" );
document.write( "\r\n" );
document.write( "\"10+=+%281.02%29%5E%284t%29\"\r\n" );
document.write( "\r\n" );
document.write( "Take logs of both sides:\r\n" );
document.write( "\r\n" );
document.write( "\"log%2810%29+=+log%281.02%5E%284t%29%29\"  \r\n" );
document.write( "\r\n" );
document.write( "Use the rule of logs:  \"log%28A%5EC%29=C%2Alog%28A%29\"\r\n" );
document.write( "\r\n" );
document.write( "\"log%2810%29+=+4t%2Alog%281.02%29\"\r\n" );
document.write( "\r\n" );
document.write( "Divide both sides by (4*log(1.02))\r\n" );
document.write( "\r\n" );
document.write( "\"log%2810%29%2F%284log%281.02%29%29+=+t\"\r\n" );
document.write( "\r\n" );
document.write( "29.06918686 years.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );