document.write( "Question 154512: determine the following products:
\n" ); document.write( "A) describe the pattern(s) you see.
\n" ); document.write( "1 x 142857, 2 x 142857, 3 x 142857. \r
\n" ); document.write( "\n" ); document.write( "B) do more computations until you can predict the next product.\r
\n" ); document.write( "\n" ); document.write( "C) alont the \"what if\" theme, this pattern seems to break at 7 X 142857. continue to find and write products of 142857 and 8,9,10, etc. what patterns do you see now \n" ); document.write( "
Algebra.Com's Answer #113767 by AnlytcPhil(1806)\"\" \"About 
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determine the following products:
\n" ); document.write( "A) describe the pattern(s) you see.
\n" ); document.write( "1 x 142857, 2 x 142857, 3 x 142857.
\n" ); document.write( "B) do more computations until you can predict the next product.
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document.write( "Do you have a calculator?  Then do what it says:\r\n" );
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document.write( "1 x 142857 = 142857\r\n" );
document.write( "2 x 142857 = 285714 \r\n" );
document.write( "3 x 142857 = 428571\r\n" );
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\n" ); document.write( "B) do more computations until you can predict the next product.
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\r\n" );
document.write( "Do what it says:\r\n" );
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document.write( "4 x 142857 = 571428\r\n" );
document.write( "5 x 142857 = 714285\r\n" );
document.write( "6 x 142857 = 857142\r\n" );
document.write( "7 x 142857 = 999999\r\n" );
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\n" ); document.write( "C) along the \"what if\" theme, this pattern seems to break at 7 X 142857. continue to find and write products of 142857 and 8,9,10, etc. what patterns do you see now.
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document.write( " 8 x 142857 = 1142856\r\n" );
document.write( " 9 x 142857 = 1285713\r\n" );
document.write( "10 x 142857 = 1428570\r\n" );
document.write( "11 x 142857 = 1571427\r\n" );
document.write( "12 x 142857 = 1714284\r\n" );
document.write( "13 x 142857 = 1857141\r\n" );
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document.write( "On all those we have have a 1 in front, followed by 1 less\r\n" );
document.write( "than the numbers in the first batch. Then \r\n" );
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document.write( "we have another break in the pattern at 14, which puts a\r\n" );
document.write( "1 in front of 1 lest than the 999999 encountered at the \r\n" );
document.write( "last break.\r\n" );
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document.write( "14 x 142857 = 1999998\r\n" );
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document.write( "Then we have\r\n" );
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document.write( "15 x 142857 = 2142855\r\n" );
document.write( "16 x 142857 = 2285712\r\n" );
document.write( "17 x 142857 = 2428569\r\n" );
document.write( "18 x 142857 = 2571426\r\n" );
document.write( "19 x 142857 = 2714283\r\n" );
document.write( "20 x 142857 = 2857140\r\n" );
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document.write( "On all those we have have a 2 in front, followed by 2 less\r\n" );
document.write( "than the numbers in the first batch. Then we have another\r\n" );
document.write( "break from the pattern at 21:\r\n" );
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document.write( "21 x 142857 = 2999997\r\n" );
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document.write( "If we keep on we'll have a break at every multiple of 7 which\r\n" );
document.write( "will add one to the 1st digit of the last break, followed by\r\n" );
document.write( "1 more less than the numbers in the first batch.\r\n" );
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document.write( "Edwin
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