document.write( "Question 154505: at a benefit concet, 600 tickets were sold and $1500 was raised. if there were $2 and $5 tickets, how many of each were sold? \n" ); document.write( "
Algebra.Com's Answer #113756 by jojo14344(1513)\"\" \"About 
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Let:
\n" ); document.write( "\"x\"=no.of $2.00
\n" ); document.write( "\"y\"=no.of $5.00
\n" ); document.write( "So, \"x%2By=600tickets\" ---------------------------------> eqn 1
\n" ); document.write( "In eqn 1 we get, \"x=600-y\" ---------------------------> eqn 2
\n" ); document.write( "Also, no.of tickets of $2.00 + no.of tickets of $5.00=$1500. To show in eqn,
\n" ); document.write( "\"2.00%28x%29%2B5.00%28y%29=1500\" --------------------------------> eqn 3
\n" ); document.write( "Substitute eqn 2 in eqn 3:
\n" ); document.write( "\"2%28600-y%29%2B5y=1500\"
\n" ); document.write( "\"1200-2y%2B5y=1500\"
\n" ); document.write( "\"3y=1500-1200\" -----> \"3y=300\"
\n" ); document.write( "\"cross%283%29y%2Fcross%283%29=cross%28300%29100%2Fcross%283%29\"
\n" ); document.write( "\"y=100\" ---------------------------> total of $5.00 tickets
\n" ); document.write( "For $2.00 tickets, go back eqn 2:
\n" ); document.write( "\"x=600-100=500\" -------------------> total of $2.00 tickets
\n" ); document.write( "In doubt? Go back eqn 3:
\n" ); document.write( "\"2%28500%29%2B5%28100%29=1500\"
\n" ); document.write( "\"1000%2B500=1500\"
\n" ); document.write( "\"1500=1500\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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