document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154505>Question 154505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at a benefit concet, 600 tickets were sold and $1500 was raised. if there were $2 and $5 tickets, how many of each were sold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113755 by </B><A HREF=/tutors/aboutme.mpl?userid=BrittanyM><B>BrittanyM(80)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BrittanyM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can use the given information to set up a system of equations and find each of the variables.\r<BR>\n" );
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document.write( "We were told that there were a total of 600 tickets sold:\r<BR>\n" );
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document.write( "x + y = 600\r<BR>\n" );
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document.write( "And that one type of ticket was sold for two dollars while the other type was sold for five dollars.  The total in sales was $1500.\r<BR>\n" );
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document.write( "2x + 5y = 1500\r<BR>\n" );
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document.write( "Now, we can manipulate the first equation to find x in terms of y.\r<BR>\n" );
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document.write( "x = 600 - y \r<BR>\n" );
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document.write( "And plug this into the second equation in order to solve for y.\r<BR>\n" );
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document.write( "2( 600 - y ) + 5y = 1500<BR>\n" );
document.write( "1200 - 2y + 5y = 1500<BR>\n" );
document.write( "3y = 300<BR>\n" );
document.write( "y = 100\r<BR>\n" );
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document.write( "We can plug this value into either of the two equations to find the value for x.\r<BR>\n" );
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document.write( "x + 100 = 600<BR>\n" );
document.write( "x = 500\r<BR>\n" );
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document.write( "So there were 100 five dollar tickets sold and 500 two dollar tickets sold, but just to be certain, we can plug these values back into either equation to check our answer.\r<BR>\n" );
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document.write( "2( 500 ) + 5( 100 ) = 1500<BR>\n" );
document.write( "1000 + 500 = 1500\r<BR>\n" );
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document.write( "Since this is true, we know that our answers are correct. </SPAN>\n" );
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