document.write( "Question 154427: a florist sold 80 stalks of lilies and threw away 1/7 of the remaining stalks of lilies.the florist has 2/5 of the lilies left. how many stalks of lilies were left?\r
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document.write( "ps. do not use algebra but if there is no choice, its okay. \n" );
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Algebra.Com's Answer #113715 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a florist sold 80 stalks of lilies and threw away 1/7 of the remaining stalks of lilies.the florist has 2/5 of the lilies left. how many stalks of lilies were left? \n" ); document.write( "; \n" ); document.write( "This is the algebra forum, so algebra is all we know about. \n" ); document.write( ": \n" ); document.write( "Let x = Original no. of lilies \n" ); document.write( "Total - sold - threw away = lilies left(given as 2/5 of the total) \n" ); document.write( "x - 80 - \n" ); document.write( ": \n" ); document.write( "Multiply equation by 35 to get rid of the denominators \n" ); document.write( "35x - 35(80) - 5(x-80) = 7(2x) \n" ); document.write( ": \n" ); document.write( "35x - 2800 - 5x + 400 = 14x \n" ); document.write( ": \n" ); document.write( "35x - 5x - 14x - 2800 + 400 = 0 \n" ); document.write( ": \n" ); document.write( "16x - 2400 = 0 \n" ); document.write( ": \n" ); document.write( "16x = 2400 \n" ); document.write( "x = \n" ); document.write( "x = 150 lilies originally \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "150 - 80 = 70 not sold \n" ); document.write( " \n" ); document.write( "60 remaineth, which is 2/5 of 150 \n" ); document.write( " \n" ); document.write( " |