document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154437>Question 154437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Seems like this should be simple...<BR>\n" );
document.write( "\"Solve for x using logs. Give an exact answer. <BR>\n" );
document.write( "4 * 2^x = 6 * 5^x \"\r<BR>\n" );
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document.write( "I tried:<BR>\n" );
document.write( "4*log2^x=6*log5^x<BR>\n" );
document.write( "log2^x^4=log5^x^6<BR>\n" );
document.write( "log2^4x=log5^6x<BR>\n" );
document.write( "log (2^4x)/(5^6x)=0<BR>\n" );
document.write( "10^0=(2^4x)/(5^6x)<BR>\n" );
document.write( "1=(2^4x)/(5^6x)<BR>\n" );
document.write( "so x=0\r<BR>\n" );
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document.write( "Which is incorrect.  I'd really appreciate some help on this one!<BR>\n" );
document.write( "T </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113712 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113712\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when taking logs, exponents become coefficients\r<BR>\n" );
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document.write( "log(4) + x log(2) = log(6) + x log(5)\r<BR>\n" );
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document.write( "subtracting xlog(2)+log(6) __ log(4)-log(6)=xlog(5)-xlog(2) __ factoring __ log(2/3)=x(log(5/2))\r<BR>\n" );
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document.write( "dividing by log(5/2) __ log(2/3)/log(5/2)=x </SPAN>\n" );
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