document.write( "Question 154328: Solution A is 80% Alcohol and Solution B is 50% Alcohol. How many Liters of each solutions should be mixed in order to make 100 Liters of a solution that is 68% alcohol? \n" ); document.write( "
Algebra.Com's Answer #113646 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let a=\"liters of Solution A\" and b=\"liters of Solution B\" __ a+b=100 __ b=100-a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(80%)a+(50%)b=(68%)100 __ .8a+.5b=68 __ substituting __ .8a+.5(100-a)=68 __ distributing __ .8a+50-.5a=68\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtracting 50 __ .3a=18 __ dividing by .3 __ a=60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting b=100-(60) __ b=40 \n" ); document.write( " |