document.write( "Question 154332: Determine whether the lines of the graph are perpendicular.
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Algebra.Com's Answer #113634 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"6x-7y=5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"-7y=5-6x\" Subtract \"6x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-7y=-6x%2B5\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-6x%2B5%29%2F%28-7%29\" Divide both sides by \"-7\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-6%29%2F%28-7%29%29x%2B%285%29%2F%28-7%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%286%2F7%29x-5%2F7\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So we can see that the equation \"y=%286%2F7%29x-5%2F7\" has a slope \"m=6%2F7\" and a y-intercept \"b=-5%2F7\".\r
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\n" ); document.write( "\n" ); document.write( "\"6y-7x=5\" Now move onto the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"6y=57x\" Add \"7x\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6y=7x%2B5\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%287x%2B5%29%2F%286%29\" Divide both sides by \"6\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%287%29%2F%286%29%29x%2B%285%29%2F%286%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%287%2F6%29x%2B5%2F6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So we can see that the equation \"y=%287%2F6%29x%2B5%2F6\" has a slope \"m=7%2F6\" and a y-intercept \"b=5%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the first line is \"m=6%2F7\" and the slope of the second line is \"m=7%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "Since the two slopes are neither equal nor negative reciprocals of one another, the two lines are neither parallel nor perpendicular.\r
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