document.write( "Question 154302: A large pump can fill a 54,000 gallon reservoir in 8 hours. Working together, the largepump and a smaller one can fill the reservoir in 6 hours. How long would it take the smaller pump to fill the reservoir by itself?\r
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Algebra.Com's Answer #113615 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Remember:
\n" ); document.write( "\"LargePump=highlight%28LP%29=54000gal%2F8hrs\" ----> condition 1
\n" ); document.write( "\"SmallPump=highlight%28SP%29=unknown\"
\n" ); document.write( "But, \"LP%2BSP=54000gal%2F6hrs\" ---------------> condition 2
\n" ); document.write( "Substitute condtn. 1 in condtn. 2:
\n" ); document.write( "\"%2854000%2F8%29%2BSP=54000%2F6\"
\n" ); document.write( "\"SP=%2854000%2F6%29-%2854000%2F8%29\". Take LCD,
\n" ); document.write( "\"SP=%28432000-324000%29%2F48=%28108000%2F48%29\" Divide both numerator/denominator by 2:
\n" ); document.write( "\"SP=cross%28108000%2954000%2Fcross%2848%2924\"
\n" ); document.write( "\"SP=54000gal%2F24hrs\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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