document.write( "Question 154298: The length of a rectangle is 5 less than thrice its width. Find the dimensions if the area is 112 squared cm. \n" ); document.write( "
Algebra.Com's Answer #113609 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Remember:
\n" ); document.write( "\"Arect=L%2AW\" -------------------------------------> working eqn
\n" ); document.write( "But \"L=3W-5\", 5 less thrice the width
\n" ); document.write( "So substitute,
\n" ); document.write( "\"A=%283W-5%29%28W%29\", distribute
\n" ); document.write( "\"112=%283w%5E2-5W%29\"
\n" ); document.write( "\"3W%5E2-5W-112=0\"
\n" ); document.write( "By Quadratic: \"a=3\", \"b=-5\", & \"c=-112\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x=%28-%28-5%29%2B-sqrt%28-5%5E2-4%2A3%2A-112%29%29%2F%282%2A3%29\"
\n" ); document.write( "\"x=%285%2B-sqrt%2825%2B1344%29%29%2F6\"
\n" ); document.write( "\"x=%285%2B-sqrt%281369%29%29%2F6\"
\n" ); document.write( "\"x=%285%2B-37%29%2F6\", It has 2 values:
\n" ); document.write( "\"x=%285%2B37%29%2F6=7\" --------------------> TO BE USED , WIDTH
\n" ); document.write( "\"x=%285-37%29%2F6=-5.33\" -----------------> DON'T USED (-)
\n" ); document.write( "Therefore,
\n" ); document.write( "\"L=3%2A7-5=21-5=16cm\"
\n" ); document.write( "\"W=7cm\"
\n" ); document.write( "In doubt? Go back working eqn:
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "\"112=16%2A7\"
\n" ); document.write( "\"112cm%5E2=112cm%5E2\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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