document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154285>Question 154285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is: Suppose that you have a supply of a 30%solution of alcohol<BR>\n" );
document.write( "and 70% of solution of alcohol. how many quartz of each should be mixed to poduce 20 quartz that is 40%alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113607 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 30% solution needed<BR>\n" );
document.write( "Then 20-x=amount of 70% solution needed\r<BR>\n" );
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document.write( "Now we know that the pure alcohol in the 30% solution (0.30x) plus the amount of pure alcohol in the 70% solution (0.70(20-x)) has to equal the amount of pure alcohol in the final mixture (0.40*20) so our equation to solve is:\r<BR>\n" );
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document.write( "0.30x+0.70(20-x)=0.40*20  get rid of parens\r<BR>\n" );
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document.write( "0.30x+14-0.70x=8  subtract 14 from each sidwe\r<BR>\n" );
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document.write( "0.30x+14-14-0.70x=8-14  collect like terms\r<BR>\n" );
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document.write( "-0.40x=-6  divide each side by -0.40<BR>\n" );
document.write( "x=15 quarts----------------------------amount of 30% solution needed<BR>\n" );
document.write( "20-x=20-15=5 quarts-----------------------amount of 70% solution needed\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "15*0.30+5*0.70=20*0.40<BR>\n" );
document.write( "4.5+3.5=8<BR>\n" );
document.write( "8=8\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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