document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154290>Question 154290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The farthest I've gotten on this one was that I had to add 1 to 12 and i had to take 50 away everytime I added 1 to 12.<BR>\n" );
document.write( "Please help me solve this equation: A jazz group on tour has been drawing average crowds of 500 persons. It is projected that for every $1 increase in the $12 ticket price, the average attendance will decrease by 50. At what ticket price will nightly receipts be $5600? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113604 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= the number of $1 increases in the ticket price.<BR>\n" );
document.write( "500*12=6000<BR>\n" );
document.write( "(500-50x)(12+x)=5600<BR>\n" );
document.write( "-50(x-10)(x+12)=5600<BR>\n" );
document.write( "(x-10)(x+12)=-112<BR>\n" );
document.write( "x^2+2x-120=-112<BR>\n" );
document.write( "x^2+2x-8=0<BR>\n" );
document.write( "(x+4)(x-2)=0<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );