document.write( "Question 154226This question is from textbook
\n" ); document.write( ": a man invested $6000, part of it at 5%simple interest and the rest at 7% simple interest. If his annual interest income is $372, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #113568 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
.07x+.05(6,000-x)=372
\n" ); document.write( ".07x+300-.05x=372
\n" ); document.write( ".02x=372-300
\n" ); document.write( ".02x=72
\n" ); document.write( "x=72/.02
\n" ); document.write( "x=$3,600 invested @7%.
\n" ); document.write( "6,000-3,600=$2,400 invested @5%.
\n" ); document.write( "Proof:
\n" ); document.write( ".07*3,600+.05*2,400=372
\n" ); document.write( "252+120=372
\n" ); document.write( "372=372
\n" ); document.write( "
\n" );