document.write( "Question 154226This question is from textbook
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document.write( ": a man invested $6000, part of it at 5%simple interest and the rest at 7% simple interest. If his annual interest income is $372, how much did he invest at each rate? \n" );
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Algebra.Com's Answer #113568 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .07x+.05(6,000-x)=372 \n" ); document.write( ".07x+300-.05x=372 \n" ); document.write( ".02x=372-300 \n" ); document.write( ".02x=72 \n" ); document.write( "x=72/.02 \n" ); document.write( "x=$3,600 invested @7%. \n" ); document.write( "6,000-3,600=$2,400 invested @5%. \n" ); document.write( "Proof: \n" ); document.write( ".07*3,600+.05*2,400=372 \n" ); document.write( "252+120=372 \n" ); document.write( "372=372 \n" ); document.write( " |