document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154267>Question 154267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Explain how to reverse FOIL, when factoring a polynomial of the form ax^2 + bx + c.When (a) is not equal to 1. Give an example\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113567 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^2-7x+2<BR>\n" );
document.write( "the factors of 3=1,3 & -1,-3<BR>\n" );
document.write( "the factors or 2=1,2 & -1,-2<BR>\n" );
document.write( "now find the sum of the products of each group of factors thus:<BR>\n" );
document.write( "1*1+3*2=7<BR>\n" );
document.write( "1*2+1*3=5<BR>\n" );
document.write( "1*-1+3*-2=-1-6=-7 eureka this is the combination.<BR>\n" );
document.write( "(3x-1)(x-2)<BR>\n" );
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