document.write( "Question 154246: Complete the square and write the equation in standard form. Then give the center and radius of the circle
\n" ); document.write( "x^2+y^2-2x-4y-4=0
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Algebra.Com's Answer #113554 by orca(409)\"\" \"About 
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\"x%5E2%2By%5E2-2x-4y-4=0\"
\n" ); document.write( "\"x%5E2%2By%5E2-2x-4y=4\"
\n" ); document.write( "\"x%5E2-2x%2By%5E2-4y=4\"
\n" ); document.write( "\"x%5E2-2x%2B1%2By%5E2-4y%2B4=4%2B1%2B4\" (add 1 and 4 to both sides of the equation)
\n" ); document.write( "\"%28x%5E2-2x%2B1%29%2B%28y%5E2-4y%2B4%29=9\"
\n" ); document.write( "\"%28x-1%29%5E2%2B%28y-2%29%5E2=3%5E2\"
\n" ); document.write( "So
\n" ); document.write( "the center is (1,2),
\n" ); document.write( "the radius is 3
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