document.write( "Question 154241: I need help trying to find out how to: write an equation in slope intercept form for the line that contains the given point and is perpendicular to the given line.
\n" ); document.write( " (2,5) , 6x+2y=24
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Algebra.Com's Answer #113547 by Alan3354(69443)\"\" \"About 
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I need help trying to find out how to: write an equation in slope intercept form for the line that contains the given point and is perpendicular to the given line.
\n" ); document.write( "(2,5) , 6x+2y=24
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\n" ); document.write( "Put 6x+2y=24 into slope-intercept form, y = mx + b
\n" ); document.write( "6x+2y=24
\n" ); document.write( "2y = -6x + 24
\n" ); document.write( "y = -3x + 12
\n" ); document.write( "The slope m is -3.
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\n" ); document.write( "A line perpendicular will have a negative inverse slope, +1/3.
\n" ); document.write( "So, (y - y1) = m*(x - x1)
\n" ); document.write( "y - 5 = (1/3)*(x - 2)
\n" ); document.write( "3y - 15 = x - 2
\n" ); document.write( "3y = x + 13
\n" ); document.write( "x - 3y = -13\r
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