document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21997>Question 21997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was not sure what category to pick so I choose test.  Sorry.  My Algebra II book calls this type of problem variation.  Anyway here is my problem:\r<BR>\n" );
document.write( "\n" );
document.write( "For a constant temperature, the pressure (P) of gas varies inversely as the volume (V).  If the pressure is 25 lb/in squared when the volume is 400 ft to the third, find the pressure when the volume is 150 ft to the third.  \r<BR>\n" );
document.write( "\n" );
document.write( "So i know the formula is y=k/x and then you substitue P=k/x.  then substitue 25 squared = k/400 third.  I think at this point I want to get rid of the denominator of 400 to the third by multiplying both sides by 400 to the third, but I am not sure.  Any help would be much appreciated.  Thank you for your time.<BR>\n" );
document.write( "                           <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11354 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon%21><B>stanbon!(97)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon%21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you are getting confused in reading your problem.<BR>\n" );
document.write( "The pressuse is 25 lb per sq. in. not (25 lb/in)^2.<BR>\n" );
document.write( "The volume is 400 cubic ft. not (400 ft.)^3.<BR>\n" );
document.write( "So you have in place of P = k/V the following:<BR>\n" );
document.write( " 25 = k/400<BR>\n" );
document.write( "  k = 10,000<BR>\n" );
document.write( "The equation you want is P= 10,000/V<BR>\n" );
document.write( "Now, find the pressure when the volume is 150 cu. ft.<BR>\n" );
document.write( "P = 10,000/150= 66 2/3 lb./sq.in\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );