document.write( "Question 154219: Factor: 125x^3 + 64 \n" ); document.write( "
Algebra.Com's Answer #113529 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"125x%5E3%2B64\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%29%5E3%2B%284%29%5E3\" Rewrite \"125x%5E3\" as \"%285x%29%5E3\". Rewrite \"64\" as \"%284%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%2B4%29%28%285x%29%5E2-%285x%29%284%29%2B%284%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%285x%2B4%29%2825x%5E2-20x%2B16%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"125x%5E3%2B64\" factors to \"%285x%2B4%29%2825x%5E2-20x%2B16%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"125x%5E3%2B64=%285x%2B4%29%2825x%5E2-20x%2B16%29\"
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