document.write( "Question 154211: (y+2)^2 = 20
\n" ); document.write( "solve for y my nephew and i both keep getting different answers
\n" ); document.write( "

Algebra.Com's Answer #113521 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B2%29%5E2=20\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2B2=0%2B-sqrt%2820%29\" Take the square root of both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y%2B2=sqrt%2820%29\" or \"y%2B2=-sqrt%2820%29\" Break up the \"plus/minus\" to form two equations.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y%2B2=2%2Asqrt%285%29\" or \"y%2B2=-2%2Asqrt%285%29\" Simplify the square root.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=-2%2B2%2Asqrt%285%29\" or \"y=-2-2%2Asqrt%285%29\" Subtract \"2\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "--------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the solutions are \"y=-2%2B2%2Asqrt%285%29\" or \"y=-2-2%2Asqrt%285%29\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "which approximate to \"y=2.472\" or \"y=-6.472\"
\n" ); document.write( "
\n" );