document.write( "Question 154198: this is not in a text book
\n" ); document.write( "400(x-1)^2=225
\n" ); document.write( "this is what I have
\n" ); document.write( "400x^2-800x+175=0
\n" ); document.write( "my instructions are solve for x
\n" ); document.write( "x= -(-800) +/- sqrt[(-800)^2 - 4(400*175)]/2(400)
\n" ); document.write( "x= [800+/- sqrt(640000-280000)] / 800
\n" ); document.write( "x= (800 +/- sqrt 360,000) /800
\n" ); document.write( "x= (800 +/- 1.000000001)/800
\n" ); document.write( "is it right up to this point? where do we go from here?
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Algebra.Com's Answer #113515 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"400%28x-1%29%5E2=225\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=%28225%29%2F%28400%29\" Divide both sides by \"400\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2=9%2F16\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=0%2B-sqrt%289%2F16%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=sqrt%289%2F16%29\" or \"x-1=-sqrt%289%2F16%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x-1=3%2F4\" or \"x-1=-3%2F4\" Take the square root of \"9%2F16\" to get \"3%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2B3%2F4\" or \"x=1-3%2F4\" Add \"1\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=7%2F4\" or \"x=1%2F4\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=7%2F4\" or \"x=1%2F4\".
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