document.write( "Question 153514This question is from textbook Algebra structure and method book 1
\n" ); document.write( ": can you please help me solve: (((Jim has a total of 50 coins. Some are nickels and some are dimes. Although he has $4.15. How many dimes does he have? How many nickels?))) \n" ); document.write( "
Algebra.Com's Answer #113508 by orca(409)\"\" \"About 
You can put this solution on YOUR website!
Let x be the number of dimes, then the number of nickels is 50 - x.
\n" ); document.write( "The value of the dimes is 10x.
\n" ); document.write( "The value of the nickels is 5(50 - x).
\n" ); document.write( "Their total is 10x + 5(50 - x).
\n" ); document.write( "As we are given that the total value is 415 cents, we have
\n" ); document.write( "10x + 5(50 - x) = 415
\n" ); document.write( "Solving for x, we obtain:
\n" ); document.write( "10x + 250 - 5x = 415
\n" ); document.write( "5x + 250 = 415
\n" ); document.write( "5x = 165
\n" ); document.write( "x = 33
\n" ); document.write( "So
\n" ); document.write( "the number of dime is 33,
\n" ); document.write( "the number of nickels is 50 - x = 50 -33 = 17.
\n" ); document.write( "
\n" ); document.write( "
\n" );