document.write( "Question 153514This question is from textbook Algebra structure and method book 1
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document.write( ": can you please help me solve: (((Jim has a total of 50 coins. Some are nickels and some are dimes. Although he has $4.15. How many dimes does he have? How many nickels?))) \n" );
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Algebra.Com's Answer #113508 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the number of dimes, then the number of nickels is 50 - x. \n" ); document.write( "The value of the dimes is 10x. \n" ); document.write( "The value of the nickels is 5(50 - x). \n" ); document.write( "Their total is 10x + 5(50 - x). \n" ); document.write( "As we are given that the total value is 415 cents, we have \n" ); document.write( "10x + 5(50 - x) = 415 \n" ); document.write( "Solving for x, we obtain: \n" ); document.write( "10x + 250 - 5x = 415 \n" ); document.write( "5x + 250 = 415 \n" ); document.write( "5x = 165 \n" ); document.write( "x = 33 \n" ); document.write( "So \n" ); document.write( "the number of dime is 33, \n" ); document.write( "the number of nickels is 50 - x = 50 -33 = 17. \n" ); document.write( " \n" ); document.write( " |