document.write( "Question 153557: The length of a rectangle is 9 centimeters more than half the width. Find the length if they perimeter is 60 centimeters. \n" ); document.write( "

Algebra.Com's Answer #113507 by orca(409) $\"\"$ $\"About$

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Let x be the width, then the length is $\"x%2F2+%2B+9\"$ .
\n" ); document.write( "The perimeter = 2*width + 2*length
\n" ); document.write( "= $\"2x+%2B+2%28x%2F2%2B9%29\"$
\n" ); document.write( "As the perimeter is 60, we have:
\n" ); document.write( " $\"2x+%2B+2%28x%2F2%2B9%29=60\"$
\n" ); document.write( "Solving for x, we have
\n" ); document.write( " $\"2x+%2B+x+%2B+18+=+60\"$
\n" ); document.write( " $\"3x%2B18=60\"$
\n" ); document.write( " $\"3x=42\"$
\n" ); document.write( " $\"x=14\"$
\n" ); document.write( "So
\n" ); document.write( "the width is 14 cm,
\n" ); document.write( "the length is $\"x%2F2+%2B+9=14%2F2%2B9=7%2B9=16+cm\"$ .
\n" ); document.write( " \n" ); document.write( "

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