document.write( "Question 154110: Chemical Products makes two insect repellents, Regular and Super. The chemical used for Regular is 15% DEET, and the chemical used for Super is 25% DEET. Each carton of repellent contains 24 ounces of the chemical. In order to justify starting production, the company must produce at least twice as many cartons of Regular as ofSuper. Labor costs are $8 per carton for Regular and $6 per carton for Super. How many cartons of each repellent should be produced to minimize labor costs if 59,400 ounces of DEET are available? I only need help setting up the problem, the rest I can get... THANKS! \n" ); document.write( "
Algebra.Com's Answer #113501 by josmiceli(19441)\"\" \"About 
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Let \"r\"= the number of cartons of Regular produced
\n" ); document.write( "Let \"s\"= the number of cartons of Super produced
\n" ); document.write( "Then,
\n" ); document.write( "\".15r\"= the amount of DEET used in \"r\" cartons of Regular
\n" ); document.write( "\".25s\"= the amount of DEET used in \"s\" cartons of Super
\n" ); document.write( "and
\n" ); document.write( "\"24%2A%28r+%2B+s%29\" is the ounces of chemical produced
\n" ); document.write( "therefore,
\n" ); document.write( "\"24%2A%28.15r+%2B+.25s%29\" is the ounces of DEET produced
\n" ); document.write( "59,400 ounces of DEET are available, so
\n" ); document.write( "\"24%2A%28.15r+%2B+.25s%29+%3C=+59400\"
\n" ); document.write( "\".15r+%2B+.25s+%3C=+2475\"
\n" ); document.write( "The problem says
\n" ); document.write( "\"r+%3E=+2s\"
\n" ); document.write( "In dollars, the labor costs are
\n" ); document.write( "\"C+=+8r+%2B+6s\"
\n" ); document.write( "These can be plotted as \"r\" vs \"s\"
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