document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=154170>Question 154170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for writing and interpreting direct variation<BR>\n" );
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document.write( "problem:  if y= -4 when x=(1/2), find y when x=(2/3)\r<BR>\n" );
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document.write( "y= kx  k= y/x k= -4/(1/2) y= -8x y= -8(2/3) y= -(16/3)\r<BR>\n" );
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document.write( "how do you find y after you plugged x into the equation?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #113496 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=113496\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> problem: if y= -4 when x=(1/2), find y when x=(2/3) <BR>\n" );
document.write( "y= kx k= y/x k= -4/(1/2) y= -8x y= -8(2/3) y= -(16/3) <BR>\n" );
document.write( "how do you find y after you plugged x into the equation??<BR>\n" );
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document.write( "Direct variation implies y = kx<BR>\n" );
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document.write( "You are told y=-4 when x = 1/2<BR>\n" );
document.write( "Solve for \"k\".<BR>\n" );
document.write( "-4 = k/(1/2)<BR>\n" );
document.write( "k = -2<BR>\n" );
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document.write( "so, the equation for your problem is y = -2x<BR>\n" );
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document.write( "Now, find y when x = 2/3<BR>\n" );
document.write( "y = -2(2/3)<BR>\n" );
document.write( "y = -4/3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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