document.write( "Question 154167This question is from textbook college algebra
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document.write( ": A liter of fluid is 50% alcohol. How much water must be added to dilute it to a 20% solution?\r
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document.write( "my work: so x is the amount of water to be added.
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document.write( " so something + x should = .20?? \n" );
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Algebra.Com's Answer #113475 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! The following fact is used to set up the equation: \n" ); document.write( "The amount of the pure alcohol before mixing must be equal to the amount of the pure alcohol after mixing. \n" ); document.write( "So \n" ); document.write( "***************************************************** \n" ); document.write( "The solution before mixing: 1L of 50% solution \n" ); document.write( "The amount of alcohol before mixing is 50%*1 \n" ); document.write( "***************************************************** \n" ); document.write( "The solution after mixing: 1+x liters of 20% solution \n" ); document.write( "The amount of alcohol after mixing is 20%*(1+x) \n" ); document.write( "*****************************************************\r \n" ); document.write( "\n" ); document.write( "So the equation is: \n" ); document.write( "50%*1 = 20%(1+x)\r \n" ); document.write( "\n" ); document.write( "Solving for x, we have \n" ); document.write( "50 = 20(1+x) (multiply both sides by 100) \n" ); document.write( "50 = 20 + 20x \n" ); document.write( "30 = 20x \n" ); document.write( "30/20 = x \n" ); document.write( "1.5 = x\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |