document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22959>Question 22959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> C takes 3 hours longer than B to walk 40 kilometers. If C doubles his rate he can cover the same distance in one hour less than B. Find the rate of each. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11345 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET B TAKE B HRS TO COVER 40 KM ...SO HIS SPEED IS 40/B...KMPH...<BR>\n" );
document.write( "C TAKES 3 HRS LONGER ..THAT IS B+3 HRS TO COVER 40 KM ..<BR>\n" );
document.write( "SO HIS SPEED IS 40/(B+3) ....<BR>\n" );
document.write( "C DOUBLES THE SPEED .SO HIS SPEED  NOW 2*40/(B+3)=80/(B+3)...SO HE NEEDS <BR>\n" );
document.write( "40/{80/(B+3)}=(B+3)/2 HRS..TO COVER 40 KM<BR>\n" );
document.write( "BUT HE TAKES 1 HR LESS THAN B ... THAT IS B-1 HRS.....SO...WE HAVE...<BR>\n" );
document.write( "(B+3)/2=B-1<BR>\n" );
document.write( "B+3=2(B-1)<BR>\n" );
document.write( "B+3=2B-2<BR>\n" );
document.write( "2B-B=3+2<BR>\n" );
document.write( "B=5....HENCE SPEED OF B IS 40/5=8 KMPH AND<BR>\n" );
document.write( "WE HAVE SPEED OF C =40/(5+3)=40/8=5 KMPH. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );